# How many moles are in 17.5 g of sodium?

## How many moles are in 17.5 g of sodium?

And we're going to end up with a value of 0.761 moles of sodium.

## How many grams of sodium are in a mole?

If you refer to your periodic table, the molar mass of Na (sodium) is 23.0 g/mol.

## How many moles is sodium?

The mole is the SI unit of amount of substance. One mole of a substance contains 6.022 times 10 to the 23rd entities of that substance. So one mole of copper atoms is 6.022 times 10 to the 23rd copper atoms. And one mole of sodium atoms is 6.022 times 10 to the 23rd sodium atoms.

## How many moles are present in 10.0 grams of sodium?

That is the molar mass 0.25. So 0.25 moles are presenting 10 grand.

## How do I calculate moles?

The unit is denoted by mol.

1. The formula for the number of moles formula is expressed as.
2. Given.
3. Number of moles formula is.
4. Number of moles = Mass of substance / Mass of one mole.
5. Number of moles = 95 / 86.94.

## How many moles is 15 grams of Na?

1 Expert Answer From 15 g of Na you got 0.65246 mol.

## How many moles are in 23g of sodium?

1 mole The number of moles of sodium atom in 23g of sodium is 1 mole.

## How many moles are there in 69 grams of sodium?

Answer: In 69 g of sodium, there are 3 moles & hence 18.066 × 10^23 atoms.

## How do I find moles from grams?

Divide the mass of the substance in grams by its molecular weight. This will give you the number of moles of that substance that are in the specified mass. For 12 g of water, (25 g)/(18.015 g/mol) = 0.666 moles.

## How many moles are in 115 g of sodium?

The answer is 22.98977. We assume you are converting between grams Sodium and mole. You can view more details on each measurement unit: molecular weight of Sodium or mol The molecular formula for Sodium is Na.

## How many moles are there in 34.5 of sodium?

1.5 moles Therefore, 34.5g of sodium contains 1.5 moles of sodium.

## Why is a mole 6.022 x10 23?

The MOLE (mol) is a unit of measurement that is the amount of a pure substance containing the same number of chemical units (atoms, molecules etc.) as there are atoms in exactly 12 grams of carbon-12 (i.e., 6.022 X 1023).

## How do you find the number of moles?

The unit is denoted by mol.

1. The formula for the number of moles formula is expressed as.
2. Given.
3. Number of moles formula is.
4. Number of moles = Mass of substance / Mass of one mole.
5. Number of moles = 95 / 86.94.

## How many moles of sodium atoms are present in 69 grams Ofsodium na?

SOLUTION. The gram atomic mass of sodium (Na) is 23 g. Thus, 23 g of sodium contains one mole of sodium atoms. Number of moles of sodium in 69 grams = 6923 = 3 moles.

## How many moles are in 15 grams of NaCl?

1 Expert Answer From 15 g of Na you got 0.65246 mol. If you use this balanced equation, you can figure out what this means for moles of NaCl and therefore how many grams of NaCl.

## How many moles are in 11.5 grams of sodium?

0.5 moles Solution : Number of moles of sodium atoms `=("mass of sodium ")/("Gram Atomic Weight") = (11.5)/(23) = 0.5` <br> i.e., 0.5 moles of Na atoms are there in the given 11.5 g sample.

## How many moles are in 23 grams of sodium?

1 mole The number of moles of sodium atom in 23g of sodium is 1 mole.

## How many moles are present in 11.5 gram of sodium?

0.5 moles Solution : Number of moles of sodium atoms `=("mass of sodium ")/("Gram Atomic Weight") = (11.5)/(23) = 0.5` <br> i.e., 0.5 moles of Na atoms are there in the given 11.5 g sample.

## What is the formula for moles to grams?

Multiply the given number of moles (2.50 mol) by the molar mass (122.548 g/mol) to get the grams.

## How many moles are in 11.5 g of sodium?

0.5 moles Solution : Number of moles of sodium atoms `=("mass of sodium ")/("Gram Atomic Weight") = (11.5)/(23) = 0.5` <br> i.e., 0.5 moles of Na atoms are there in the given 11.5 g sample.

## How many sodium atoms are in 11.5 grams of sodium?

So there are 3.011*10^23 atoms present in 11.5g of sodium sample.

## How many moles are in 11.5 grams?

There are 0.5 moles present in 11.5 g of sodium.