How many strings of length 8 consisting of uppercase English letters are there if no letter can be repeated?
Number of bit strings of length 8 that start with 1 and end with 00: 25 = 32. Applying the subtraction rule the number is 128 + 64 − 32 = 160.
How many strings of eight English letters are there that contain no vowels if letters Cannot be repeated?
There are 26 possible letters. By part (a), there are 37 , 822 , 859 , 361 37,822,859,361 37,822,859,361 strings with no vowels.
How many strings of five uppercase English letters are there 1 if letters can be repeated?
The answer. So 35152 is the answer.
How many combinations are there in an 8 character password?
An eight-character password using only lowercase and uppercase characters has 200 billion possible combinations. Given a reasonably powerful workstation (100,000,000 guesses per second), we could brute force our way through all of the possible combinations in around 30 min.
How many bit strings of length n are palindromes if’n is even and if’n is odd?
How many bit strings of length n are palindromes? The answer is: 2n+12 for odd and 2n2 for even.
How many bit strings of length 10 contain an equal number of 0s and 1s?
We subtract from the total number of bit strings of length 10 those that have only 0, 1, 2 or 3 1s. = 1024 − 1 − 10 − 45 − 120 = 848. d) an equal number of 0s and 1s? = 10!/(5!
How many strings of 4 lower case English are possible?
We're only considering lowercase letters, repetition is allowed. 264−254=66,351 strings. This is one solution.
How many strings are there of lower case letters of length four or less not counting the empty string?
To form a string of lowercase of length 4, need to choose 4 letters from the 26 lower case alphabets. Here, each of the 4 letters can be chosen in 26 ways, as each letter is in lower case.
How many combinations of 8 numbers are there with repeats?
Or perhaps you meant the number of 8 digit numbers (repetitions permitted) using the digits 0-9. In that case, each digit has 10 choices and there are 8 of them, so the answer is 108 = 100 000 000.
How long does it take to crack a password of 8 characters?
The findings suggest that even an eight-character password — with a healthy mix of numbers, uppercase letters, lowercase letters and symbols — can be cracked within eight hours by the average hacker.
How many different bit strings of length 8 are there?
256 How many bit strings are there of length 8? There are 28 which is 256. That means there are 256 different values you can store in a byte, since a byte is eight bits.
How many bit strings of length 8 either start with a 1 or end with a 00?
160 Number of bit strings of length 8 that start with 1 and end with 00: 25 = 32. Applying the subtraction rule, the number is 128 + 64 − 32 = 160.
What is the number of bit strings of length 8 where the number of 0’s is equal to the number of 1’s?
What is the number of bit-strings (that is, strings consisting of 0's and 1's) of length 8 where the number of 0's is equal to the number of 1's? answer is: 70. See what the community says and unlock a badge.
How many bit strings of length 8 contains an equal number of 0’s and 1’s?
When you have chosen were to place the 0's in the bit string the indices of the 1's are automatically determined. You have (84) possibilities to place the 0's, and therefore (84) possible strings with equal number of 0's and 1's.
How many strings of 4 digit numbers do not contain the same digit twice?
Based on the product rule, we conclude that there are 10 × 9 × 8 × 7 = 5040 four decimal digits that do not contain the same digit twice.
How many strings of six lowercase letters from the English alphabet contain the letter a and B?
Hence, the number of strings of six distinct lower case letters from the English alphabet that contain the letters a and b in consecutive positions with a preceding b is (244)⋅5!
How many bit strings of length 8 either start with a 1 bit or end with the two bits 00?
The correct answer is "option 3". Hence, the number of bit strings of length 8 that will either start with 1 or end with 00 is 160.
How many bit strings are there of length eight?
How many bit strings are there of length 8? There are 28 which is 256. That means there are 256 different values you can store in a byte, since a byte is eight bits.
How many combinations of 8 items have no repeats?
40,320 different combinations Note: 8 items have a total of 40,320 different combinations.
How many combinations of 8 letters are there?
An eight-character password using only lowercase and uppercase characters has 200 billion possible combinations.
How many passwords are possible with 8 digits?
Combination and length of the password
| Password consists of | Possible combinations |
|---|---|
| 8 characters (4 lowercase letters, 2 special characters, 2 numbers) | 688= 457,163,239,653,376 |
| 9 characters (2 uppercase letters, 3 lowercase letters, 2 numbers, 2 special characters) | 949= 572,994,802,228,616,704 |
How many different 8 bit strings are there that begin and end with one *?
How many 8-bit strings begin and end with 1? Answer : 26 since first and last bit have been already determined. How many 8-bit strings have either the second or the fourth bit 1 (or both)?
How many strings exists of length 8 either start with 1 or end with 00?
160 The correct answer is "option 3". Hence, the number of bit strings of length 8 that will either start with 1 or end with 00 is 160.
How many 8 bit strings can be constructed such that first digit is 1 or the last digit is 1?
Case 1: First binary digit is 1. Given this condition, all possible strings with attribute fulfill the required 'Or' condition. So there are 27 strings in this set.
How many bit strings of length 8 are there?
How many bit strings are there of length 8? There are 28 which is 256. That means there are 256 different values you can store in a byte, since a byte is eight bits.
How many 8-bit strings that is bit strings of length 8 are there which?
How many bit strings are there of length 8? There are 28 which is 256. That means there are 256 different values you can store in a byte, since a byte is eight bits.
How many 8-bit strings can be constructed such that first digit is 1 or the last digit is 1?
Case 1: First binary digit is 1. Given this condition, all possible strings with attribute fulfill the required 'Or' condition. So there are 27 strings in this set.
How many possible way you can make your 4 digit PIN if there is no number repeated?
There are 10 possible values for each digit of the PIN (namely: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9), so there are 10 · 10 · 10 · 10 = 104 = 10,000 total possible PIN numbers. To have no repeated digits, all four digits would have to be different, which is selecting without replacement.
How many combinations consisting of 4 digits can be made using the digits from 0 to 9?
10,000 possible combinations There are 10,000 possible combinations that the digits 0-9 can be arranged into to form a four-digit code.
How many strings of 6 letters contain the letter a?
As a result, there are 64,775,151 possible strings of six letters that contain the letter a . It is required to determine the number of strings of six letters that contain a and b in the form ab with all letters being distinct.