What gives a single Monochlorination product?

What gives a single Monochlorination product?

Therefore, the compound which gives only one monochlorination product on its chlorination in the presence of sunlight is neopentane.

Which one of the following gives a single Monochlorination product a 2 2 dimethylpropane B 2 3 Dimethylbutane C 2 2 Dimethylbutane D 2 Methylpropane?

Answer and Explanation: The answer is c) 2,2-dimethylpropane.

Which of the following alkanes give only one Monochlorinated product?

CH3(CH2)3CH3.

How many Monochlorination products are possible in the reaction of 2 2 Dimethylbutane with chlorine in the presence of ultraviolet light?

So Totally 4 Compounds are Possible on monochlorination of 2-methylbutane.

Which of the following gives only one chlorination product?

neo-Pentane or 2, 2-dimethylpropane has only primary hydrogen hence it can give only monochloro derivative.

How many Monochlorination products can be formed?

Total fourteen monochlorinated products can be obtained from all the isomeric alkanes having the formula C5H10 (excluding stereoisomers).

Which one of the following hydrocarbons when treated with chlorine will give only single Monochloro compounds?

Solution : neo-Pentane or 2,2-dimethylpropane has only primary hydrogen hence it can give only monochloro derivative.

Which of the following will give four mono chloro products on chlorination in the presence of sunlight?

On treatment with chlorine in presence of sunlight toluene gives the product . On treatment with chlorine in presence of sunlight toluene gives the product .

How do you find Monochlorinated products?

To find the number of monochlorinated products, the only way is to find the number of structures drawn. Complete answer: Monochlorination of an alkane involves substituting one of the hydrogen in the alkane with a chlorine atom. This is achieved by treating the alkane with chlorine in the presence of UV light.

How do you calculate Monochlorination product?

To find the number of monochlorinated products, the only way is to find the number of structures drawn. Complete answer: Monochlorination of an alkane involves substituting one of the hydrogen in the alkane with a chlorine atom. This is achieved by treating the alkane with chlorine in the presence of UV light.

How many Monochlorination products are possible for?

Total fourteen monochlorinated products can be obtained from all the isomeric alkanes having the formula C5H10 (excluding stereoisomers). These are as shown.

Which of the following compounds gives only one Monochloro product on its chlorination in presence of sunlight?

neo-pentane Reason:- All the hydrogen of neo-pentane are primary that's why it gives only one mono chloro product.

What is meant by Monochlorination?

The action or process of introducing a single chlorine atom into a molecule.

What are Monochlorination products?

Monochlorination of an alkane involves substituting one of the hydrogen in the alkane with a chlorine atom. This is achieved by treating the alkane with chlorine in the presence of UV light. These conditions cause the chlorine molecule to split into chlorine free radicals.

How many types of Monochlorination are there?

Correct answer is '8'.

Which of the following will give only one Monochloro derivative after reaction with cl2 in presence of sunlight is 😕

neo-Pentane or 2, 2-dimethylpropane has only primary hydrogen hence it can give only monochloro derivative.

Which of the following will give four chlorinated products on Monochlorination?

A compound `(C_5H_8)` gives with ppt. with ammonical `AgNO_3` and on reduction followed by monochlorination it gives 4 structrual monochloro products. What is the possible structure of compound ?

How many Monochlorination products are formed?

Free Radical Halogenation Of Methane And Ethane Can Give Only One Monochlorinated Product.

How many Monochlorination products are possible?

Total fourteen monochlorinated products can be obtained from all the isomeric alkanes having the formula C5H10 (excluding stereoisomers). These are as shown.

What is Monochlorination product?

Monochlorination of an alkane involves substituting one of the hydrogen in the alkane with a chlorine atom. This is achieved by treating the alkane with chlorine in the presence of UV light. These conditions cause the chlorine molecule to split into chlorine free radicals.

Which of the following compounds can only give one Monochlorinated product upon free radical chlorination?

Therefore 2, 2 Dimethyipropane is the compound that can yeild only one monochlorinated product upon free radical chlorination.

How many products are formed from Monochlorination?

Total fourteen monochlorinated products can be obtained from all the isomeric alkanes having the formula C5H10 (excluding stereoisomers). These are as shown.

How many products of Monochlorination are there?

Total fourteen monochlorinated products can be obtained from all the isomeric alkanes having the formula C5H10 (excluding stereoisomers).

What C5H12 isomer will give only a single Monochlorination product?

Answer and Explanation: Single monochlorination product is obtained from neopentane which is an isomer of C5H12 C 5 H 12 .

What is a Monochlorination product?

Monochlorination of an alkane involves substituting one of the hydrogen in the alkane with a chlorine atom. This is achieved by treating the alkane with chlorine in the presence of UV light. These conditions cause the chlorine molecule to split into chlorine free radicals.

Which one of the following hydrocarbons will form only one Monochloro derivative with?

Solution : neo-Pentane or 2,2-dimethylpropane has only primary hydrogen hence it can give only monochloro derivative.

How many compounds will give only one Monochloro structural isomers?

So total 4 monochloro structural isomers formed.

How do you find the product of Monochlorination?

To find the number of monochlorinated products, the only way is to find the number of structures drawn. Complete answer: Monochlorination of an alkane involves substituting one of the hydrogen in the alkane with a chlorine atom. This is achieved by treating the alkane with chlorine in the presence of UV light.

Which one of the following compounds is only one product on Monobromination?

Hence `H` forms only one product on monobromination.

How many Monochlorination products may be obtained when the alkane?

∴ Total 8 monochloro products.